If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(H)=-16H^2+150H+90
We move all terms to the left:
(H)-(-16H^2+150H+90)=0
We get rid of parentheses
16H^2-150H+H-90=0
We add all the numbers together, and all the variables
16H^2-149H-90=0
a = 16; b = -149; c = -90;
Δ = b2-4ac
Δ = -1492-4·16·(-90)
Δ = 27961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-149)-\sqrt{27961}}{2*16}=\frac{149-\sqrt{27961}}{32} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-149)+\sqrt{27961}}{2*16}=\frac{149+\sqrt{27961}}{32} $
| 7.4=-t/1.5 | | 3n-16=n2-6n+3 | | -17=0.5k | | Y=150+75x | | −17=−0.5k | | 12x-8=14x-10 | | 11k^2=-8k-4 | | 20-2d=5 | | 21=2(5x-2) | | 42=5x-2 | | 8(-1+m)+3=2(m-5~1/2) | | 8(-1+m)+3=2(m-5`1/2) | | 88+88+x=180 | | 8(-1+m)+3=2(m-5,1/2) | | 2x=0.5/x | | -61=-4(s-4)-7s | | 3(x-2)+x=3x+3 | | 9(p-8)-3p=-12 | | 31=-6d+9d-2 | | -10+j=8−j | | -5-n=-5 | | 4p=-3+7p | | 48=6+7(b-2) | | -5m+7=-18 | | 274x=9x+1 | | 8(-1+m)+3=2(m-5+1/2) | | (x-2)^2=-9 | | (x/2)*4=8.3 | | 8n+10=-54 | | x^2+12x+144=7+144 | | 14x+10-3x=32 | | -3n+7=41- |